2d Parity Check Program C

Posted : admin | On 15-09-2021

2d Parity Check Program Cal
2d Parity Check Program Code
2d Parity Check Program In C

Which of the following statements is true about a two-dimensional parity check (2D-parity) computed over a payload? 2D-parity can detect any case of a single bit flip in the payload. 2D-parity can detect and correct any case of a single bit flip in the payload. If the rightmost bit is 1, then n will have odd parity and if it is 0 then n will have even parity. We check the odd or even by using bitwise AND operator. If (b & 1) is true means odd else even. C program to find parity of a number efficiently. So, here is the C implementation of the above algorithm. Active Oldest Votes. To find the matching pairs in columns, scan over each row except the last, and for each column, compare the value at array row col with the value at array row+1 col and report matches. To find the matching pairs in rows, scan over each column except the last, and for each row, compare the value at.

In this tutorial, we are going to learn how to find parity of a number efficiently in C++. Here we will learn about the parity of a number, algorithm to find the parity of a number efficiently, and after that, we will see the C++ program for the same.

Simple Parity-Check Code: The simple parity-check code is the most familiar error-detecting code. In this code, a k-bit data word is changed to an n-bit code word where n = k + 1. The extra bit, called the parity bit, is selected to make the total number of 1s in the code word even. Although some implementations specify an odd number of 1s.
That is, the rows have been encoded using odd parity and the last row holds the parity bits of the columns which have also been encoded using odd parity. There are two possible interpretations of the corner parity bit in the last block – it can either check the row or column parity. In this example, it has been used to check the column parity.

Parity of a number

Parity of a number is a term used to tell that the total number of set bits(1’s) in its binary representation is even or odd. It is of two types:-
1. Even Parity: If the total number of set bits (1’s) is even, then that number has even parity.
2. Odd Parity: If the total number of set bits (1’s) is odd, then that number has odd parity.
For example:-
12 has even parity because it has an even number of set bits in its binary representation i.e ‘1100’.
14 has odd parity because it has an odd number of set bits in its binary representation i.e ‘1110’.

Efficient Algorithm to find parity of a number

The most efficient way of finding the parity of a number is by using XOR and shifting operator as shown below.
b = n ^ (n >> 1);
b = b ^ (b >> 2);
b = b ^ (b >> 4);
b = b ^ (b >> 8);
b = b ^ (b >> 16);

In the above operations, we use XOR and left shift operator. We are shifting double bits of the previous operation. And taking the XOR with that number. We know that 0 XOR 1 or 1 XOR 0 is 1, otherwise 0. So when we divide the binary representation of a number into two equal halves by length & we do XOR between them, all different pairs of bits result into set bits in the result number i.e “b” here.

Now, after the above operations b contain the rightmost bit of b and represent the parity of n. If the rightmost bit is 1, then n will have odd parity and if it is 0 then n will have even parity.
We check the odd or even by using bitwise AND operator. If (b & 1) is true means odd else even.

C++ program to find parity of a number efficiently

So, here is the C++ implementation of the above algorithm:-

Output:-

Thanks for reading this tutorial. I hope it helps you !!

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